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Thread: Modulus

  1. #1
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    Modulus

    Cannot figure it out why it is like that considering x and k positive...
    Please anyone can explain it to me? Thx
    I mean why it is like that and not: cos(x/k)-1 ?

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  2. #2
    Junior Member Cervesa's Avatar
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    Re: Modulus

    $-1 \le \cos(x/k) \le 1 \implies \cos(x/k)-1 \le 0$ and $1-\cos(x/k) \ge 0$
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