Can anyone explain to me why the image is true?
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Originally Posted by aprilcm Can anyone explain to me why the image is true? Note: This is only true if B is not a function of s! $\displaystyle \int_C \dfrac{\vec{B} \cdot \vec{B}}{B}~ds = \int_C \dfrac{B^2}{B}~ds = \int_C B~ds = B \int_C ds$ -Dan
Note that the vector $\vec{B}$ (or B) might depend upon s as long as B (the magnitude of $\vec{B}$) does not.
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