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Math Help - Need help with homework again

  1. #1
    Newbie
    Joined
    Jan 2008
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    13

    Need help with homework again

    The height of an object above the ground at time "t" is given by

    s = (v_0)t - (g/2)t^2

    where V_0 is the initial velocity and "g" is the acceleration due to gravity.

    (a) At what height is the object initially?
    (b) How long is the object in the air before it hits the ground?
    (c) When will the object reach its maximum height?
    (d) What is that maximum height?

    Well, I know the answer to a is 0, but I'm not sure about the rest of them, any help at least setting them up?
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  2. #2
    Super Member
    Joined
    Oct 2007
    From
    London / Cambridge
    Posts
    591
    b)

    let s = 0, there are two solution, one when t =0 at the start and other whn ti comes back down.

    c) find out when the velocity is zero, use calculus or v = u + at

    d) plug the time into the expression for displacement.
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