This comes from the review true/false quiz for chapter 10 of the fifth edition ofCalculus with Analytic Geometryby Purcell and Varberg:

$f(x) = x^{5/2}$ has a second-order Maclaurin polynomial.

I answered false because $P_{2}(0) = f(0) + f'(0)x + \frac{f''(0)}{2}x^2$, $f'(x) = \frac{5}{2}x^{3/2}, f''(0) = \frac{15}{4}x^{1/2}$ and $f(0) = f'(0) = f''(0) = 0$. The answer key says true.