So im doing a double integral question, i will avoid posting whole question as is kinda wordy but essentialy:

z=((x-y)^2)/4

and both x and y are defined in the region of a square (+/- 1,+/-1)

i am a little unsure what to set bounds of the integrals as i dont know if the minuses will affect the value. do i just set up the double integral with bound (+1,-1) or is there something more complicated.

Any help will be greatly appreciated, many thanks.