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Thread: Find angle for maximized volume of trapezoid

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    Find angle for maximized volume of trapezoid

    I need help on thisFind angle for maximized volume of trapezoid-img_2321-min-1-.jpg
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    Re: Find angle for maximized volume of trapezoid

    Quote Originally Posted by animalpants View Post
    I need help on thisClick image for larger version. 

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    Find angle for maximized volume of trapezoid-trap.gif
    Area of the trapezoid is $A=\dfrac{1}{2}h(U+L)$ U is the upper base and $U=2x+10$ & lower base is $L=10$
    Because the bases of a trapezoid are parallel the upper angle is $\theta$, alternate angles.
    Using trigonometry we get $\cos(\theta)=\frac{x}{10}~\&~\sin(\theta)=\frac{h }{10} $

    Now we are able to expresss area $A(\theta)$ and maximize using $d\theta$ .
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    Re: Find angle for maximized volume of trapezoid

    thanks
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