f(x)=((x^3)-1)/((x^2)-1), x=1
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Originally Posted by wbarner f(x)=((x^3)-1)/((x^2)-1), x=1 $\displaystyle f(x) = \left\{ {\begin{array}{*{20}{rl}} {\frac{{{x^3} - 1}}{{{x^2} - 1}},}&{x \ne 1}\\ {\frac{3}{2},}&{x = 1} \end{array}} \right.$
Thank you but can you tell me how you did this
Originally Posted by wbarner Thank you but can you tell me how you did this Well, for one thing I learned how to factor: $\displaystyle \dfrac{{{x^3} - 1}}{{{x^2} - 1}} = \dfrac{{(x - 1)({x^2} + x + 1)}}{{(x - 1)(x + 1)}} = \dfrac{{({x^2} + x + 1)}}{{(x + 1)}},~x \ne 1$
Ah crap, your right. Thank you