I need to find the point in the plane x + 2y + 3z = 6 that is nearest the origin.

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- February 12th 2008, 03:25 PMchaddyclosest point
I need to find the point in the plane x + 2y + 3z = 6 that is nearest the origin.

- February 12th 2008, 03:32 PMecMathGeek
- February 12th 2008, 03:34 PMchaddy
How would I find the normal vector?

- February 14th 2008, 08:34 PMchaddy
Does anyone know?

- February 14th 2008, 09:00 PMmr fantastic
- February 14th 2008, 09:06 PMmr fantastic
So the parametric equations of the line passing through the origin and in the direction of this normal vector will be:

x = at

y = bt

z = ct

The point where this line cuts the plane will be the point that's closest to the origin:

.

Therefore the coordinates of the point in the plane closest to the origin are:

.

.

.

And as a bonus, the answer to what the closest distance is equal to is .......... - February 15th 2008, 01:10 AMchaddy

So the point closest to the origin would be < , , > - February 15th 2008, 01:58 AMmr fantastic