Hello,

When I solved $\int e^{2x}*\cosh(x)dx$, I got the answer $(\frac{-\sinh(x)}{3}+\frac23\cosh(x))*e^{2x}+C$. But the answer provided is $\frac{e^{3x}}{6}+\frac{e^x}{2}+C$.Both answers are equal. I want to know which identity is used for making both of them equivalent?