# Thread: I need some help at least starting this out.

1. ## I need some help at least starting this out.

A baseball hit at an angle of "X" to the horizontal with initial velocity "V" has horizontal range, R , given by

$\displaystyle R = (((V^2)/g)sin(2x))$

Here "g" is the acceleration due to gravity. Sketch "R" as a function of "x" for $\displaystyle 0 <= x <= (pi/2)$ . What angle "Xmax" gives the maximum range? What is the maximum range "Rmax" ?

2. Originally Posted by billabong7329
A baseball hit at an angle of "X" to the horizontal with initial velocity "V" has horizontal range, R , given by

$\displaystyle R = (((V^2)/g)sin(2x))$

Here "g" is the acceleration due to gravity. Sketch "R" as a function of "x" for $\displaystyle 0 <= x <= (pi/2)$ . What angle "Xmax" gives the maximum range? What is the maximum range "Rmax" ?
the graph of sin(2x) is exactly the same as sin(x), except now, the period is pi as opposed to 2pi. the constant multiple in front changes the amplitude, so the graph will go up to a max of (V^2)/g and down to a min of -(V^2)/g

3. Ok, wow, I thought way too much into the question and totally didn't see any of that.

So the X max ended up being "pi/4" and I got the question right.

Thanks, I appreciate it as always.

4. Originally Posted by billabong7329
Ok, wow, I thought way too much into the question and totally didn't see any of that.

So the X max ended up being "pi/4" and I got the question right.

Thanks, I appreciate it as always.
you're very much welcome