IF dy/dx= squareroot(x/y) and y=4 then x=1, what is the equation y?
Last edited by emilyastrid; Jul 30th 2018 at 09:22 AM.
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Originally Posted by emilyastrid IF dy/dx= squareroot(x/y) and y=4 then x=1, y =??? You just told us that $y=4$. Now you want to know what y is equal to? It is still 4.
i meant the equation y.
Originally Posted by emilyastrid i meant the equation y. You have $$\dfrac{dy}{dx} = \sqrt{\dfrac{x}{y}}$$ Multiplying out gives: $$\sqrt{y}dy = \sqrt{x}dx$$ You can rewrite as: $$y^{1/2}dy = x^{1/2}dx$$ Now, integrate both sides. Plug in $(1,4)$ to determine the constant of integration. Solve for $y$.
Originally Posted by emilyastrid IF dy/dx= squareroot(x/y) and y=4 then x=1, what is the equation y? You have a typo- you meant to say "y= 4 when x= 1" or, more simply, "y(1)= 4".
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