y=3x^2-x^3

P= (1,2)

y=

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- Feb 12th 2008, 11:51 AMplstevensFind the equation of the tangent line to the following curve at the given point P. Il
y=3x^2-x^3

P= (1,2)

y= - Feb 12th 2008, 02:32 PMmr fantastic
- Feb 12th 2008, 05:47 PMplstevens
I still don't understand

- Feb 12th 2008, 05:56 PMmr fantastic
- Feb 12th 2008, 06:34 PMplstevens
is it y=3x-1

- Feb 12th 2008, 08:00 PMmr fantastic