show why lim x->0+ 1/x - 1/(x^2)= -inf
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$\displaystyle \frac{1}{x}- \frac{1}{x^2}= \frac{x}{x^2}- \frac{1}{x^2}= \frac{x- 1}{x^2}$. For x close to 0 the numerator is negative while the denominator is positive.