I have r =2 and r=3+2sintheta
--> 2=3+2sintheta
---> sintheta = -1/2
theta = 4pi/3 , 11pi/6
coordinates (4pi/3,2), (11pi/6,2)
Did i do something wrong?
Actually it should be points in the form $\displaystyle (r, ~ \theta )$, not $\displaystyle ( \theta, ~ r)$.
I'm getting $\displaystyle sin( \theta) = -1/2 \implies \theta = -\frac{\pi}{6} + \pi = \frac{5 \pi}{6} \text{ and } \theta = -\frac{\pi}{6} + 2 \pi = \frac{11 \pi}{6}$
-Dan