I have r =2 and r=3+2sintheta

--> 2=3+2sintheta

---> sintheta = -1/2

theta = 4pi/3 , 11pi/6

coordinates (4pi/3,2), (11pi/6,2)

Did i do something wrong?

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- Apr 25th 2018, 06:58 PMlc99coordinates of intersection for polar curves
I have r =2 and r=3+2sintheta

--> 2=3+2sintheta

---> sintheta = -1/2

theta = 4pi/3 , 11pi/6

coordinates (4pi/3,2), (11pi/6,2)

Did i do something wrong? - Apr 25th 2018, 07:14 PMtopsquarkRe: coordinates of intersection for polar curves
Actually it should be points in the form $\displaystyle (r, ~ \theta )$, not $\displaystyle ( \theta, ~ r)$.

I'm getting $\displaystyle sin( \theta) = -1/2 \implies \theta = -\frac{\pi}{6} + \pi = \frac{5 \pi}{6} \text{ and } \theta = -\frac{\pi}{6} + 2 \pi = \frac{11 \pi}{6}$

-Dan - Apr 25th 2018, 07:26 PMlc99Re: coordinates of intersection for polar curves
would 5pi/6 give positive value?

- Apr 26th 2018, 11:47 AMtopsquarkRe: coordinates of intersection for polar curves