I'm asked to find the slope of the tangent to the graph of the function at the point whose x-coordinate is given...

for the function: f(x)=x^-3(x^(-1)+1); x=1.

So simplifying...

f(x)=x^-3(x^(-1)+1)

f(x)=(1/x^3)(1/x+1)

f(x)=(1/3x^2)(2)

f(x)=2/3

Where do I go from here?