$$\frac{tan^3(x)+tan(x)}{tan^3(x)+3tan^2(x)+2tan(x )+6}dx$$
Help section in the book tells to use substitution t=tan(x) so $$dx=cos^2(t) dt$$:
$$\frac{t^3+t}{t^3+3t^2+2t+6}cos^2(t) dt$$
How do i continue from here? Is this a good path to take?
$$\frac{tan^3(x)+tan(x)}{tan^3(x)+3tan^2(x)+2tan(x )+6}dx$$
Help section in the book tells to use substitution t=tan(x) so $$dx=cos^2(t) dt$$:
$$\frac{t^3+t}{t^3+3t^2+2t+6}cos^2(t) dt$$
How do i continue from here? Is this a good path to take?