The eqn is :
y" +y' +y = (sin(x))^2
and i'm in need of a particular solution, y(p).
I tried y=Asin(x)^2, but am not getting anywhere.
y = A*sin(x)^2
y' = Asin(2x)
y'' = 2Acos(2x)
Follow Math Help Forum on Facebook and Google+
solved it, no worries.
Last edited by jblorien; Feb 11th 2008 at 01:56 PM.
View Tag Cloud