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Math Help - Particular Solution Diff EQ

  1. #1
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    Particular Solution Diff EQ

    The eqn is :

    y" +y' +y = (sin(x))^2

    and i'm in need of a particular solution, y(p).

    I tried y=Asin(x)^2, but am not getting anywhere.

    y = A*sin(x)^2
    y' = Asin(2x)
    y'' = 2Acos(2x)

    best,
    jblorien
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  2. #2
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    \sin^2 x = \frac{1}{2} - \frac{1}{2}\cos 2x
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  3. #3
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    solved it, no worries.
    Last edited by jblorien; February 11th 2008 at 01:56 PM.
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