find the equation of the tangent line to y=(sin x)^4x at the point (pi/2, 1)

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- Feb 10th 2008, 11:24 PMBust2000tangent line
find the equation of the tangent line to y=(sin x)^4x at the point (pi/2, 1)

- Feb 10th 2008, 11:55 PMJhevon
- Feb 10th 2008, 11:57 PMearboth
Do you really mean:

......**??**

If so re-write f to:

...... and use the chain rule to calculate the derivative:

Now plug in to calculate the slope of the tangent.

Since and too you'll get:

and therefore the equation of the tangent is

EDIT: According to Jhevons reply the equation of the tangent is - Feb 11th 2008, 12:04 AMJhevon