Use algebra to evaluate the limit exactly. lim(h->0) (1/(a+h) - 1/a)/h
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Originally Posted by bluejewballs Use algebra to evaluate the limit exactly. lim(h->0) (1/(a+h) - 1/a)/h I saw you there, Jhevon. Beat you on this one . I'm gonna go back and edit now And here's the edit: Get a common denominator: Simplify: . Therefore: . The limit should now be obvious.
Last edited by mr fantastic; February 9th 2008 at 07:28 PM.
thanks i kept getting 1/a^2 and i was told that was wrong.
Originally Posted by bluejewballs thanks i kept getting 1/a^2 and i was told that was wrong. that is wrong. it is -1/a^2 if you have any acquaintance with calculus, you'll realize this limit gives the derivative (by its definition) of 1/a with respect to a
Originally Posted by bluejewballs thanks i kept getting 1/a^2 and i was told that was wrong. So you see why the correct numerator is -1 ...?
Originally Posted by Jhevon that is wrong. it is -1/a^2 if you have any acquintance with calculus, you'll realize this limit gives the derivative of 1/a with respect to a beat me by 5 seconds .....payback time, hey?
Originally Posted by mr fantastic beat me by 5 seconds .....payback time, hey? exactly!
yeah i understand that it is -1 i just made a stupid mistake like i always do
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