# Thread: Need help with a definite integral problem

2. ## Re: Need help with a definite integral problem

Originally Posted by BlackRaven

Because $f$ is an even function we have $\int_{ - 2}^2 {f(x)dx} = 2\int_0^2 {f(x)dx}$
$\displaystyle \int_{-2}^2 f(x) - 8 \, dx = \int_{-2}^2 f(x) \, dx - \int_{-2}^2 8 \, dx = 2\int_0^2 f(x) \, dx - 2\int_0^2 8 \, dx = 2\int_0^2 f(x) \, dx - 32 = 8$