Use a taylor series to conjecture the value of:
The limit as x approaches 0 of (sin (x^3)-(x^3))/9
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You know that for small x (so certainly for x approaching 0), we can say that sin(x) =~ x. This follows from its Taylor series, when we neglect higher order terms (since sin(x) = x - x³/3! + ...).
So, what happens when you replace sin(x) by x?
please see the attachment
Originally Posted by bobby77 please see the attachment It's not exactly how I would have done it, but it looks close enough.
Originally Posted by bobby77 please see the attachment First order would've been enough here