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Thread: Linear Differential Equation

  1. #1
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    Exclamation Linear Differential Equation

    dy/dx + 2y/x = (cosx)/x

    So far I have:

    P(x) = 2/x
    Q(x) = (cosx)/x
    Integrating Factor: e^2lnx

    So I times both sides by the integrating factor and get:

    e^2lnx * y' + e^2lnx * 2y/x = e^2lnx * (cosx)/x

    Now when I integrate both sides, how am I supposed to integrate (cosx)/x without using Taylor series?
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  2. #2
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    Re: Linear Differential Equation

    Can't you simplify e^{2\ln x} using logarithmic identities?
    Thanks from KiaraG16
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  3. #3
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    Re: Linear Differential Equation

    Oh of course! Thank you so much!
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