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Thread: how to solve for x when there is x and lnx??

  1. #1
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    how to solve for x when there is x and lnx??

    So, I have : -4-4x+(x^2)ln(x) = 0

    i tried this but cant get x!

    4+4x = x^2 * lnx
    e^(4+4x) = e^ (lnx ^(x^2))

    I'm stuck.

    This is the orginal equation..
    how to solve for x when there is x and lnx??-capture.png
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  2. #2
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    how to solve for x when there is x and lnx??

    As far as i know, it cant be solve with analytical solution... since
    lnx = (4+4x)/x^2
    has 2 different type of function (LHS is a logarithm function, RHS is a reciprocal function)

    But however, Newton Method can help u easily to estimate the value of x
    Thanks from lc99
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  3. #3
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    Re: how to solve for x when there is x and lnx??

    ok thank you. Hopefully i dont get a problem like this on the exam XD
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  4. #4
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    Re: how to solve for x when there is x and lnx??



    This is an expression, not an equation.

    Can you provide some context as to where it came from?
    Thanks from topsquark
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  5. #5
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    Re: how to solve for x when there is x and lnx??

    Hey lc99,
    I have just discovered that what I trying to tell you is actually "Transcendental Equation"... you can wiki your own if you interested


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