# Thread: how to solve for x when there is x and lnx??

1. ## how to solve for x when there is x and lnx??

So, I have : -4-4x+(x^2)ln(x) = 0

i tried this but cant get x!

4+4x = x^2 * lnx
e^(4+4x) = e^ (lnx ^(x^2))

I'm stuck.

This is the orginal equation..

2. ## how to solve for x when there is x and lnx??

As far as i know, it cant be solve with analytical solution... since
lnx = (4+4x)/x^2
has 2 different type of function (LHS is a logarithm function, RHS is a reciprocal function)

But however, Newton Method can help u easily to estimate the value of x

3. ## Re: how to solve for x when there is x and lnx??

ok thank you. Hopefully i dont get a problem like this on the exam XD

4. ## Re: how to solve for x when there is x and lnx??

This is an expression, not an equation.

Can you provide some context as to where it came from?

5. ## Re: how to solve for x when there is x and lnx??

Hey lc99,
I have just discovered that what I trying to tell you is actually "Transcendental Equation"... you can wiki your own if you interested

Sent from my iPhone using Tapatalk