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Thread: Calculus problem(I have attached the picture of the question)

  1. #1
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    Calculus problem(I have attached the picture of the question)

    Calculus problem(I have attached the picture of the question)-cal1.png
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  2. #2
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    Re: Calculus problem(I have attached the picture of the question)

    The question is asking you to use implicit differentiation. Have you covered implicit differentiation? For part (b), you should plug in $x=1$ to the equation to find all values for $y$ that satisfy the equation (you will have an easily solvable quadratic equation). Once you find the two values of $y$ that satisfy the equation, you will have two points to find the derivative.

    Please identify specifically where you are having trouble with this problem. I can easily come up with a solution, but it may not address your specific area of concern.
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  3. #3
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    Re: Calculus problem(I have attached the picture of the question)

    The equation is 3x- 2y^2e^{x- 1}= 2 and you want to determine \frac{dy}{dx}. Do you know what the derivative of "3x", with respect to x, is? What about the derivative of "2"? To differentiate the term 2y^2e^{x- 1} you can use the "product rule" first. (2y^2e^{x- 1})'= 2y^2(e^{x- 1})'+ 2(y^2)'(e^{x- 1}). To differentiate y^2, with respect to x, use the chain rule.
    Last edited by HallsofIvy; Oct 2nd 2017 at 01:14 PM.
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