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- February 7th 2008, 11:12 AM #1

- February 7th 2008, 01:06 PM #2

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- February 7th 2008, 01:16 PM #3

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- February 7th 2008, 04:20 PM #4

- February 7th 2008, 06:38 PM #5

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- February 8th 2008, 05:24 AM #6

- February 8th 2008, 08:36 AM #7

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- November 6th 2008, 06:53 PM #8
Sorry I'm bored.

Consider some function . Let . Let the function also posses the charcteristic . So now we seek a Fourier Series to describe this function. This series will be of the form

Where is a number such that

So for and we have

Now

And is odd which implies that

Therefore we can see that

Solving gives

I'm sure this is solution is common...I'm not sure though...I found this today while tinkering.

- November 7th 2008, 10:38 AM #9

- November 7th 2008, 12:16 PM #10

- November 11th 2008, 09:21 PM #11

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