for this equation: y=xlnx i got y'=lnx+1 and theres no critical values.. so how do i get htis
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Originally Posted by s0urgrapes for this equation: y=xlnx i got y'=lnx+1 and theres no critical values.. so how do i get htis The drivative is correct. Solve for x: $\displaystyle \ln(x)+1=0~\iff~\ln(x)=-1~\iff~x=\frac1{e^x}$ Therefore you get a minimum point at $\displaystyle M\left(\frac1{e^x} , -\frac1{e^x}\right)$
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