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Thread: equation

  1. #1
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    equation

    solve (d^2)y/d(x^2) =y given that dy/dx =1 and y=1 when x=0


    i am not sure how to do this. what should the limits for v dv be ?
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  2. #2
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    Re: equation

    $y''=y $ implies an exponential solution. Try $ke^x $ where $k $ is an arbitrary constant. You get $y''=ke^x $. Then you plug in $y(0)=1$ and find $k=1$. So, I get $y=e^x $ is a solution.
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  3. #3
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    Re: equation

    Quote Originally Posted by SlipEternal View Post
    $y''=y $ implies an exponential solution. Try $ke^x $ where $k $ is an arbitrary constant. You get $y''=ke^x $. Then you plug in $y(0)=1$ and find $k=1$. So, I get $y=e^x $ is a solution.
    sorry I am not really sure of you method.


    this is what i am used to .
    equation-ioe.png

    question 1 is the worked answer to the question. i am not sure where they get v=1 as it is not given in the question.
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