1. ## equation

solve (d^2)y/d(x^2) =y given that dy/dx =1 and y=1 when x=0

i am not sure how to do this. what should the limits for v dv be ?

2. ## Re: equation

$y''=y$ implies an exponential solution. Try $ke^x$ where $k$ is an arbitrary constant. You get $y''=ke^x$. Then you plug in $y(0)=1$ and find $k=1$. So, I get $y=e^x$ is a solution.

3. ## Re: equation

Originally Posted by SlipEternal
$y''=y$ implies an exponential solution. Try $ke^x$ where $k$ is an arbitrary constant. You get $y''=ke^x$. Then you plug in $y(0)=1$ and find $k=1$. So, I get $y=e^x$ is a solution.
sorry I am not really sure of you method.

this is what i am used to .

question 1 is the worked answer to the question. i am not sure where they get v=1 as it is not given in the question.