# Thread: volume 6 sides

1. ## volume 6 sides

compute the volume of the solid
bounded by the planes
x=0
×=7
z=y-2
z=-2y-2
z=0
z=2

2. ## Re: volume 6 sides

We have \displaystyle \begin{align*} 0 \leq x \leq 7 \end{align*}, \displaystyle \begin{align*} 0 \leq z \leq 2 \end{align*} and \displaystyle \begin{align*} - \frac{z}{2} - 1 \leq y \leq z + 2 \end{align*}. Set up a triple integral.

3. ## Re: volume 6 sides

so what would that look like?

4. ## Re: volume 6 sides

Originally Posted by bigwave
so what would that look like?
What kind a question is that?
This is your problem, so show some effort.

5. ## Re: volume 6 sides

i did on w|a but answer was not correct

6. ## Re: volume 6 sides

Originally Posted by bigwave
i did on w|a but answer was not correct
ProveIt gave you the limits

$I = \displaystyle \int_0^7 \int_0^2 \int_{-\frac z 2 - 1}^{z+2}~dy~dz~dx$

7. ## Re: volume 6 sides

ok i did
$dxdydz$

8. ## Re: volume 6 sides

ok thanks everybody
never did triples before