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Thread: volume 6 sides

  1. #1
    Super Member bigwave's Avatar
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    volume 6 sides

    compute the volume of the solid
    bounded by the planes
    x=0
    =7
    z=y-2
    z=-2y-2
    z=0
    z=2
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  2. #2
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    Re: volume 6 sides

    We have $\displaystyle \begin{align*} 0 \leq x \leq 7 \end{align*}$, $\displaystyle \begin{align*} 0 \leq z \leq 2 \end{align*}$ and $\displaystyle \begin{align*} - \frac{z}{2} - 1 \leq y \leq z + 2 \end{align*}$. Set up a triple integral.
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  3. #3
    Super Member bigwave's Avatar
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    Re: volume 6 sides

    so what would that look like?
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  4. #4
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    Re: volume 6 sides

    Quote Originally Posted by bigwave View Post
    so what would that look like?
    What kind a question is that?
    This is your problem, so show some effort.
    Thanks from romsek
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  5. #5
    Super Member bigwave's Avatar
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    Re: volume 6 sides

    i did on w|a but answer was not correct
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  6. #6
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    Re: volume 6 sides

    Quote Originally Posted by bigwave View Post
    i did on w|a but answer was not correct
    ProveIt gave you the limits

    $I = \displaystyle \int_0^7 \int_0^2 \int_{-\frac z 2 - 1}^{z+2}~dy~dz~dx$
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  7. #7
    Super Member bigwave's Avatar
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    Re: volume 6 sides

    ok i did
    $dxdydz$
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  8. #8
    Super Member bigwave's Avatar
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    Cool Re: volume 6 sides

    ok thanks everybody
    never did triples before
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