# Thread: Simplifying derivative part 2

1. ## Simplifying derivative part 2

Hi,

I'm significantly confused about the steps that brought line 1 to line 2 of the expression below:

Can someone please provide the in-between steps? Reallly appreciate it.

2. ## Re: Simplifying derivative part 2

second term ... note $\cot{x} \cdot \sec{x} = \csc{x}$

third term ... note $\csc{x} \cdot \tan{x} = \sec{x}$

go back and study your basic trig identities