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Thread: Integral of 1/(1-x)

  1. #1
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    Integral of 1/(1-x)

    Yeah so basically we all know that the integral of 1/(1-x) is -ln(1-x)+c, but if I factor out -1 from the denominator before integration I seem to get -ln(x-1)+c. Can someone explain where the mistake is?
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  2. #2
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    Re: Integral of 1/(1-x)

    If you're integrating $\dfrac{1}{1-x}$ over its domain, then the antiderivative is $-\ln|1-x| + C = -\ln|x-1|+C$ ... point being, $|x-1| = |1-x|$
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  3. #3
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    Re: Integral of 1/(1-x)

    Oookay yep thanks
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