ｔｈｅｒｅ ａｒｅ ｔｗｏ ｆｕｎｃｔｉｏｎｓ： ｆ（ｘ）＝（１／８）ｘ－３ ａｎｄ ｇ（ｘ）＝ｘ＾３ ｈｏｗ ｄｏ ｙｏｕ ｆｉｎｄ ｆ＾－１（ｇ＾－１（１））？
Follow Math Help Forum on Facebook and Google+
Originally Posted by got_jane ｔｈｅｒｅ ａｒｅ ｔｗｏ ｆｕｎｃｔｉｏｎｓ： ｆ（ｘ）＝（１／８）ｘ－３ ａｎｄ ｇ（ｘ）＝ｘ＾３ ｈｏｗ ｄｏ ｙｏｕ ｆｉｎｄ ｆ＾－１（ｇ＾－１（１））？ why don't you type with spaces? to find , start with switch x and y and solve for y. that will give you . do a similar thing to find . can you continue?
Originally Posted by Jhevon why don't you type with spaces? to find , start with switch x and y and solve for y. that will give you . do a similar thing to find . can you continue? and and so , I get 11 as an answer, but I checked the back of the book the correct answer is supposed to be 32...I wonder what I'm doing wrong.
Originally Posted by got_jane and and so , I get 11 as an answer, but I checked the back of the book the correct answer is supposed to be 32...I wonder what I'm doing wrong. your function for is wrong. it is
Originally Posted by Jhevon your function for is wrong. it is oh! I got it! thank you so much! i appreciate it!
View Tag Cloud