Hi!
The problem says:
A region R in the plane consists of those points (x,y) which satisfy the inequalities
1_<x^2+y^2<_4
0_<x
0_<y
And the intgral is
SSR (x^2+y^2-1)dA
(a screenshot of the problem is attached)
Thanks in advance!
Hi!
The problem says:
A region R in the plane consists of those points (x,y) which satisfy the inequalities
1_<x^2+y^2<_4
0_<x
0_<y
And the intgral is
SSR (x^2+y^2-1)dA
(a screenshot of the problem is attached)
Thanks in advance!
Convert to polar coordinates. This gives you $1\le r \le 2$ and $0 \le \theta \le \dfrac{\pi}{2}$.
$\displaystyle \int_0^{\tfrac{\pi}{2}} \int_1^2 (r^2-1)r{dr}{d\theta} = \int_0^{\tfrac{\pi}{2}}\dfrac{9}{4}{d\theta} = \dfrac{9\pi}{8}$