If $\displaystyle

\frac{{df}}{{dx}}=x^x

$ for x>0, and $\displaystyle

g(x)=f(x^2)$ then $\displaystyle

\frac{{dg}}{{dx}} =

$ ?

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- Feb 4th 2008, 03:37 PM #1

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- Feb 4th 2008, 06:12 PM #2

- Feb 4th 2008, 06:57 PM #3

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- Feb 4th 2008, 07:13 PM #4