Question as is

Compute the area of the finite region bounded by the graphs of the functions

y=2x^{2}, and y=-2x^{2}-8x+32

So i first set them equal to each other to find my points.

2x^{2}=-2x^{2}-8x+32

-4x^{2}-8x+32=0

-4(x+4)(x-2)=0

x=-4, x=2

so when I integrate it will be from the limit of -4 to 2 right?

this is where I get stuck.