Here's the question I have:
The radius of a sphere is increasing at a constant rate of 2cm/sec. At the instant when the volume of the sphere is increasing at 32pi cm^3/sec, the surface area of the sphere is
So far I have dr/dt=2, and when dv/dt=32, SA=?
I'm not sure how to relate these two equations. I assume I would solve for the radius of the sphere first, by finding the derivative of the Volume equation: dv/dt=4pir^2dr/dt, but I don't know what to do after that.