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Thread: Simple derivation of trigonometric func.

  1. #1
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    Red face Simple derivation of trigonometric func.

    please help to derive y=sin4 (sec2 3x) , I would like to know how to get the answer
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  2. #2
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    Re: Simple derivation of trigonometric func.

    Quote Originally Posted by MRina View Post
    please help to derive y=sin4 (sec2 3x) , I would like to know how to get the answer
    $(f\circ g\circ h(x))'=(f'\circ g\circ h(x))(g'\circ h(x))(h'(x))$
    Thanks from skeeter
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  3. #3
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    Re: Simple derivation of trigonometric func.

    Is this correct?
    d/dx= 24 sec^2(3x) tan(3x) cos(sec^2 (3x)) sin^3 (sec^2 (3x))
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  4. #4
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    Re: Simple derivation of trigonometric func.

    Quote Originally Posted by MRina View Post
    Is this correct?
    d/dx= 24 sec^2(3x) tan(3x) cos(sec^2 (3x)) sin^3 (sec^2 (3x))
    Yes, good for you.

    Just as a matter of style I would encourage writing is "chain form".
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