How to find the integral 1/x from 1 to 2 using riemann sum?

∫ 1/x dx = lim as n goes infinity Σ(i = 1 to n)f(xi)Δx

Δx = 2-1/n = 1/n

xi = 1 + iΔx = 1 + (i/n)

= lim as n goes infinity Σ(i = 1 to n)f(1 + (i/n))(1/n) = lim as n goes infinity Σ(i = 1 to n)[ 1 / (1 + (i/n)) ] (1/n) = lim as n goes infinity Σ(i = 1 to n)[ 1 / (n + i) ]

NOW, how to get rid of i?