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Thread: differentiate 8te^-t

  1. #1
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    differentiate 8te^-t

    how do you differentiate 8te^-t
    i tried to put it into one of them differential calculators but i cant understand the steps.

    this is how i thought if would work

    using the product rule 8t*e^-t-1 +e^-t*8 i dont think this is the right answer
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    Re: differentiate 8te^-t

    $\dfrac{d}{dt}\left( 8te^{-t}\right) = 8t \cdot \left[e^{-t} \cdot (-1)\right] + e^{-t} \cdot 8 = -8te^{-t} + 8e^{-t} = 8e^{-t}(1-t)$

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    Re: differentiate 8te^-t

    soon is there a link i could follow to do it?i see what i was doing wrong. i was treating e^-x wrong
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    Re: differentiate 8te^-t

    Quote Originally Posted by markosheehan View Post
    soon is there a link i could follow to do it?i see what i was doing wrong. i was treating e^-x wrong
    Why not just learn the product rule? $\large{(f\cdot g)'=(f'\cdot g)+(f\cdot g')}$
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    Re: differentiate 8te^-t

    Quote Originally Posted by markosheehan View Post
    soon is there a link i could follow to do it?i see what i was doing wrong. i was treating e^-x wrong
    There is an entire forum on this site devoted to it ...

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    Re: differentiate 8te^-t

    Quote Originally Posted by markosheehan View Post
    soon is there a link i could follow to do it?i see what i was doing wrong. i was treating e^-x wrong
    Yes, you are treating " e^t" as if it were " t^e". The derivative of t^e, with respect to t is et^{e- 1} but the derivative of e^t is e^t.
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