I have absolutely no idea what to do here. Please help. for -180˚ ≤ Ө ≤ 180˚, solve 1) tan^2 3Ө= 1 for 0˚ ≤ Ө ≤ 360˚, solve 2) 2sin^2 Ө = cos3Ө thanks Ө= theta
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Originally Posted by lra11 I have absolutely no idea what to do here. Please help. for -180˚ ≤ Ө ≤ 180˚, solve 1) tan^2 3Ө= 1 ... $\displaystyle \tan^2(3\theta)=1~\iff~\tan(3\theta)=1 ~\vee~\tan(3\theta)=-1$...$\displaystyle \iff~3\theta = 45°~\vee~3\theta=-135°~\vee~3\theta=-45°~\vee~3\theta=135°$ ...and now you can easily calculate $\displaystyle \theta$
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