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**JamieG** Let *s*(*t*)=2*t*2−8*t*+2 for 0≤*t*≤7 denote the position of an object moving along a line. Find

a) Velocity at time t: v(t)=s'(t)= 4t-8

b) Acceleration at time t: v'(t)= 4

c) Initial position: 2(0)-8(0)+2= 2

d) Ending position: 2(7)^2-8(7)+2= 44

--I am having trouble with this part--

e) Total distance traveled: I went the simple route since it started at 2 and ended at 44, I answered 42, but that's not correct.

f) Velocity is positive on the interval: (2,7]

--And this part--

g) Acceleration is positive on the interval [0,??

Since it was a closed interval for the equation, and the acceleration shows to be constant, 4, I tried [0,7], and [0,7), neither of which is right.