Math Help - Indefinite Integrals

1. Indefinite Integrals

How do i determine the indefinite integral of the function

Code:
f(x)= 1/(x+1)(x-3)
where (-1 < x < 3)

Cheers

2. Try partial fractions.

$\frac{1}{(x+1)(x-3)}=\frac{A}{x+1}+\frac{B}{x-3}$

3. Originally Posted by moolimanj
f(x)= 1/(x+1)(x-3)
Don't apply partial fractions, apply algebra:

$\frac{1}
{{(x + 1)(x - 3)}} = \frac{1}
{4} \cdot \frac{{(x + 1) - (x - 3)}}
{{(x + 1)(x - 3)}} = \frac{1}
{4}\left( {\frac{1}
{{x - 3}} - \frac{1}
{{x + 1}}} \right).$