How do i determine the indefinite integral of the function Code: f(x)= 1/(x+1)(x-3) where (-1 < x < 3) Cheers
f(x)= 1/(x+1)(x-3)
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Try partial fractions.
Originally Posted by moolimanj f(x)= 1/(x+1)(x-3) Don't apply partial fractions, apply algebra:
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