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Math Help - Indefinite Integrals

  1. #1
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    Indefinite Integrals

    How do i determine the indefinite integral of the function

    Code:
    f(x)= 1/(x+1)(x-3)
    where (-1 < x < 3)

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  2. #2
    Eater of Worlds
    galactus's Avatar
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    Try partial fractions.

    \frac{1}{(x+1)(x-3)}=\frac{A}{x+1}+\frac{B}{x-3}
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  3. #3
    Math Engineering Student
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    Quote Originally Posted by moolimanj View Post
    f(x)= 1/(x+1)(x-3)
    Don't apply partial fractions, apply algebra:

    \frac{1}<br />
{{(x + 1)(x - 3)}} = \frac{1}<br />
{4} \cdot \frac{{(x + 1) - (x - 3)}}<br />
{{(x + 1)(x - 3)}} = \frac{1}<br />
{4}\left( {\frac{1}<br />
{{x - 3}} - \frac{1}<br />
{{x + 1}}} \right).
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