Hello, I don't understand why the answer for the domain is wrong.
Can anyone tell me the correct answer?
Thank you.
$Q(x)$ isn't defined for $x = \sqrt[3]{3}$
therefore the domain of $Q(x)$ is $(-\infty, \sqrt[3]{3}) \cup (\sqrt[3]{3},\infty)$
$Q(x)$ is however continuous at all the points in it's domain.
It's not continuous at $x=\sqrt[3]{3}$ but that point isn't in it's domain.