1. ## continuity problem (domain)

Hello, I don't understand why the answer for the domain is wrong.

Can anyone tell me the correct answer?

Thank you.

2. ## Re: continuity problem (domain)

$Q(x)$ isn't defined for $x = \sqrt[3]{3}$

therefore the domain of $Q(x)$ is $(-\infty, \sqrt[3]{3}) \cup (\sqrt[3]{3},\infty)$

$Q(x)$ is however continuous at all the points in it's domain.

It's not continuous at $x=\sqrt[3]{3}$ but that point isn't in it's domain.