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Thread: continuity problem (domain)

  1. #1
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    continuity problem (domain)



    Hello, I don't understand why the answer for the domain is wrong.

    Can anyone tell me the correct answer?

    Thank you.
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  2. #2
    MHF Contributor
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    Re: continuity problem (domain)

    $Q(x)$ isn't defined for $x = \sqrt[3]{3}$

    therefore the domain of $Q(x)$ is $(-\infty, \sqrt[3]{3}) \cup (\sqrt[3]{3},\infty)$

    $Q(x)$ is however continuous at all the points in it's domain.

    It's not continuous at $x=\sqrt[3]{3}$ but that point isn't in it's domain.
    Thanks from Plato
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