a) Use the ratio test. (abs convergent)Originally Posted by zee
b) Use the limit comparison test with n^(-1/2). (divergent)
c) Use the ratio test or the root test, or estimate 2^3n/(n^n) < (8/9)^n for n >9 (abs convergent)
I am totally lost... need some HELP...
Classify each of the series as absolutely convergent,
conditionally convergent, or divergent.
a) (Sigma n=1..inf) (4^2n)/((-5)^n)
b) (Sigma n=1..inf) sin(1/n^1/2)
c) (Sigma n=1..inf) (-1)^n-1(2^3n)/(n^n)
please help... im not thorough with sequences and series at all..
zee