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Math Help - Find the horizontal and vertical asymptotes of the curve.

  1. #1
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    Find the horizontal and vertical asymptotes of the curve.



    x=
    x=
    y=
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  2. #2
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    The vertical asymptotes will appear when the denominator is 0. So you need to solve x^2+x-2 = 0

    The horizontal asymptote is the value for y when x approaches \infty or -\infty. Can you do it now?
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  3. #3
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    Quote Originally Posted by badgerigar View Post
    [snip]
    The horizontal asymptote is the value for y when x approaches \infty or -\infty.
    In other words, you consider the two limits:

    y = \lim_{x \rightarrow +\infty} \frac{7x^2 + x - 9}{x^2 + x - 2}, and

    y = \lim_{x \rightarrow -\infty} \frac{7x^2 + x - 9}{x^2 + x - 2}.

    In this case, the limits have the same value.
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    how do u find this value
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  5. #5
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    Quote Originally Posted by mr fantastic View Post
    In other words, you consider the two limits:

    y = \lim_{x \rightarrow +\infty} \frac{7x^2 + x - 9}{x^2 + x - 2}, and

    y = \lim_{x \rightarrow -\infty} \frac{7x^2 + x - 9}{x^2 + x - 2}.

    In this case, the limits have the same value.
    y = \lim_{x \rightarrow +\infty} \frac{7x^2 + x - 9}{x^2 + x - 2} = \lim_{x \rightarrow +\infty} \frac{7 + \frac{1}{x} - \frac{9}{x^2}}{1 + \frac{1}{x} - \frac{2}{x^2}}= \frac{7 + 0 - 0}{1 + 0 - 0} = ......
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