Decide whether to integrate with respect to x or y. Then find the area of the region. y=2x, y=4x^2 Not really sure how to begin this problem. Any help is appreciated. Thank you
Follow Math Help Forum on Facebook and Google+
You could do either. wrt x: $\displaystyle \int_{0}^{\frac{1}{2}}[2x-4x^{2}]dx$ wrt y: $\displaystyle \int_{0}^{1}[\sqrt{\frac{y}{4}}-\frac{y}{2}]dy$ I believe x is easier.
Thank you! the answer was 0.0833333...
Yes, very good. Except write 1/12 instead. Looks better.
View Tag Cloud