Hiya
I need to deriv y=0.25*sin(4pi*T)
Am new to this kinda derving but i think it should be somthing like
0.25*cos(8pt*T)
but i think am way off can anyone please give me a hand.
I also need to find the curving amp. curving period
This is just the chain rule:
$\displaystyle y=0.25*sin(4\pi*T)$
constant stays out front, sin -> cos then find the derivative of what is inside of sin
$\displaystyle \frac{dy}{dT}=0.25*cos(4\pi T)(\frac{dy}{dt}4\pi T)$
$\displaystyle \frac{dy}{dT}=0.25cos(4\pi T)(4\pi)$
And simplify
$\displaystyle \frac{dy}{dT}=\pi cos(4\pi T)$
Just look at it like this, c is the constant coefficient. f(x) is sin(x) and g(x) is $\displaystyle 4\pi T$ then you are taking the derivative of $\displaystyle c f[g(x)]$ which is $\displaystyle c * f\prime [g(x)] * g\prime (x)$
If any of that was confusing, I can explain it in more detail.