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Math Help - converging, absolutely, conditionally or diverging.

  1. #1
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    converging, absolutely, conditionally or diverging.

    here is the problem: http://img255.imageshack.us/img255/4224/54516302vs6.png

    it completely looks like it would diverge.

    could i use the direct comparison test to show that?

    first it can't converge absolutely because the absolute value of the series is a divergent p series p <= 1 not meeting the standards of a p series.

    also, could i compare this to the harmonic series and show that the original series in the pic, is actually larger than the harmonic series, showing that it diverges alltogether.

    thanks.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by rcmango View Post
    here is the problem: http://img255.imageshack.us/img255/4224/54516302vs6.png

    it completely looks like it would diverge.

    could i use the direct comparison test to show that?

    first it can't converge absolutely because the absolute value of the series is a divergent p series p <= 1 not meeting the standards of a p series.

    also, could i compare this to the harmonic series and show that the original series in the pic, is actually larger than the harmonic series, showing that it diverges alltogether.

    thanks.
    it is not a p-series

    use the alternating series test. that should be the first one you look at since you saw the (-1)^n

    whenever you see (-1)^n, look at the alternating series test first
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  3. #3
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    Quote Originally Posted by rcmango View Post
    here is the problem: http://img255.imageshack.us/img255/4224/54516302vs6.png

    it completely looks like it would diverge.

    could i use the direct comparison test to show that?

    first it can't converge absolutely because the absolute value of the series is a divergent p series p <= 1 not meeting the standards of a p series.

    also, could i compare this to the harmonic series and show that the original series in the pic, is actually larger than the harmonic series, showing that it diverges alltogether.

    thanks.
    It diverges since the general term does not tends to zero.
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