Given that z = 5 – 12i express √z in the form a + bi where a, b Є R. How can I expressed this?
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The easyest way of doing this is convert the complex number to polar form then take the square root and convert back to cartesian.
Can you explain more?
Originally Posted by geton Can you explain more? sure, I also strongly suggest that you read: Complex number - Wikipedia, the free encyclopedia
Originally Posted by geton Given that z = 5 – 12i express √z in the form a + bi where a, b Є R. How can I expressed this? Here's another way: Let Therefore . Equate real and imaginary parts: .... (1) .... (2) Sub (2) into (1): . The solution is rejected because it gives non-real values of a. . . Given how the numbers fall out, I'd say this was the method the question writer had in mind .....
Originally Posted by Peritus sure, I also strongly suggest that you read: Complex number - Wikipedia, the free encyclopedia Thank you so much. I got it
Originally Posted by mr fantastic Here's another way: Let Therefore . Equate real and imaginary parts: .... (1) .... (2) Sub (2) into (1): . The solution is rejected because it gives non-real values of a. . . Given how the numbers fall out, I'd say this was the method the question writer had in mind ..... Yes I forgot that. Thank you
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