Thread: Revenge of the Integrals

Just when I thought I was getting good at integration and logarithms, I encountered this question:

Find indefinite integral of 3^(2x-1)

I'm sure the method is quite simple-- I just want to know how to get to the solution [3^(2x-1)]/2ln3. Any help would be greatly appreciated!

Originally Posted by Sophie

Just when I thought I was getting good at integration and logarithms, I encountered this question:

Find indefinite integral of 3^(2x-1)

I'm sure the method is quite simple-- I just want to know how to get to the solution [3^(2x-1)]/2ln3. Any help would be greatly appreciated!

,

and from there the rest should be easy.

RonL

This isn't as rigorous, but think of integration in terms of the opposite of differentiation.

Take the expression . Remember that We multiply by the derivative when differentiating, so we must divide by it when integrating. . Again, not rigorous but it might help visualize the method.